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Show that if f is a twice-differentiable function such that f(0)=1, f'(0)=-1, f(1)=2, f'(1)=5, and f"(x)>=0 for all x, then f(x)>=1/3 for all 0<=x<=1.

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asked Nov 19, 2015 in Calculus by w_reguser (1,420 points)

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