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Solve equation

0 votes

e^x - e^{-x} = e

asked Oct 9, 2015 in Calculus by w1002 (660 points)

1 Answer

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Take the natural log of each term on each side:

ln e^x - ln e ^{-x} = lne^1

x - (-x) =1

2x = 1, x = 1/2

answered Oct 11, 2015 by 32fun (6,320 points)
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