# Solve equation

0 votes

$e^x - e^{-x} = e$

asked Oct 9, 2015 in Calculus

## 1 Answer

0 votes

Take the natural log of each term on each side:

$ln e^x - ln e ^{-x} = lne^1$

$x - (-x) =1$

2x = 1, x = 1/2

answered Oct 11, 2015 by (6,320 points)