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Find y(1) if

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\frac{dy}{dx} = x y^2 \text { and } y(0) =1.

asked Oct 9, 2015 in Calculus by w1002 (660 points)

1 Answer

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\int \frac{1}{y^2} dy = \int xdx

-\frac{1}{y} = \frac{1}{2}x^2 +C

Plug in coordinate (0, 1)

-1 = 0+C, C = -1

When x = 1:

-\frac{1}{y} = \frac{1}{2}1^2 +(-1) = -.5

y = 2

answered Oct 12, 2015 by 32fun (6,320 points)
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