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Determine the molar mass of the following compound.

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Ammonium Dichromate ((NH4)2Cr2O7)

asked Aug 23, 2015 in Chemistry by frang (1,700 points)

1 Answer

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1 mol ((NH4)2Cr2O7) x (2 mol N)/(1 mol ((NH4)2Cr2O7)) x (14.01 g N)/(1 mol N) = 28.02 g N

1 mol ((NH4)2Cr2O7) x (8 mol H)/(1 mol ((NH4)2Cr2O7)) x (1.01 g N)/(1 mol N) = 8.08 g H

1 mol ((NH4)2Cr2O7) x (2 mol Cr)/(1 mol ((NH4)2Cr2O7)) x (52.00 g N)/(1 mol N) = 104.0 g Cr

1 mol ((NH4)2Cr2O7) x (7 mol O)/(1 mol ((NH4)2Cr2O7)) x (16.00 g N)/(1 mol N) = 112.0 g O

28.02 + 8.08 + 104.00 + 112.0 = 252.1 g

The molar mass of ammonium dichromate is 252.1 g/mol

answered Sep 13, 2015 by thb (2,000 points)
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